Linux中通过进程ID获取程序的启动路径
shell脚本如下：
#!/bin/sh
if [ "0$1" == "0" ]; then
echo "Usage: $0 PID";exit 1;
fi
if [[ $1 =~ "^[0-9]*$" ]]; then
num=`ps -ef|grep -i $1|grep -v grep|grep -v $0|wc -l`
if [ $num -gt "1" ]; then
echo "Get too many process, please look: /proc/$1";exit 1;
fi
ps -ef|grep -i $1|grep -v grep|grep -v $0|awk '{print $2,system("ls -l /proc/"$2)}'|grep cwd
else
echo "Usage: $0 PID";exit 1;
fi
exit 0